How do you solve $2x+5y=11$ and $4x+3y=1$ using substitution?

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Answer 1 · 2018-03-05T16:01:29

$y=3,x=-2$

We have $2x=11-5y$

Multiplying both sides by $2$ ,we get $4x=22-10y$

substituting this value in $2$ nd equation,we have,

$22-10y=1-3y$

Or, $21=7y$

Thus,we get, $y=3$ and substituting this value in first equation we get $x$ as $-2$

How do you solve 2x+5y=112x+5y=11 and 4x+3y=14x+3y=1 using substitution?