How do you solve #2x+5y=11# and #4x+3y=1# using substitution? Algebra Systems of Equations and Inequalities Systems Using Substitution 1 Answer Shreya · Jane Mar 5, 2018 Answer: #y=3,x=-2# Explanation: We have #2x=11-5y# Multiplying both sides by #2#,we get #4x=22-10y# substituting this value in #2#nd equation,we have, #22-10y=1-3y# Or,#21=7y# Thus,we get, #y=3# and substituting this value in first equation we get #x# as #-2# Related questions How do you solve systems of equations using the substitution method? How do you check your solutions to a systems of equations using the substitution method? When is the substitution method easier to use? How do you know if a solution is "no solution" or "infinite" when using the substitution method? How do you solve #y=-6x-3# and #y=3# using the substitution method? How do you solve #12y-3x=-1# and #x-4y=1# using the substitution method? Which method do you use to solve the system of equations #y=1/4x-14# and #y=19/8x+7#? What are the 2 numbers if the sum is 70 and they differ by 11? How do you solve #x+y=5# and #3x+y=15# using the substitution method? What is the point of intersection of the lines #x+2y=4# and #-x-3y=-7#? See all questions in Systems Using Substitution Impact of this question 916 views around the world You can reuse this answer Creative Commons License