How do you solve #2x + 7= 3x - 4#?

1 Answer
Jim G.
Feb 12, 2017

#x=11#

Explanation:

Collect terms in x on the left side of the equation and numeric values on the right side.

subtract 3x from both sides.

#2x-3x+7=cancel(3x)cancel(-3x)-4#

#rArr-x+7=-4#

subtract 7 from both sides.

#-xcancel(+7)cancel(-7)=-4-7#

#rArr-x=-11rArrx=11" is the solution"#

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