Question

How do you solve `2x + 7 > 5`?

Answer 1

`x > -1`

Explanation:

We can treat this like a simple algebra problem, what we do to one side, we do to the other...

Subtract 7 from both sides:

`2x + 7 color(red)(- 7) > 5 color(red)(- 7`

`=> 2x > -2`

Divide both sides by 2:

`=> (2x)/ (color(red)(2) ) > (-2)/color(red)(2)`

`=> color(blue)(x > -1`

Answer 2

`x> -1`

Explanation:

`"isolate 2x by subtracting 7 from both sides of the inequality"`

`2xcancel(+7)cancel(-7)>5-7`

`rArr2x> -2`

`"divide both sides by 2"`

`(cancel(2) x)/cancel(2)>(-2)/2`

`rArrx> -1`

`(-1,+oo)larrcolor(blue)"in interval notation"`