How do you solve #2x-7=6+x#?

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Answer 1 · 2016-02-13T05:14:51

#color(green)(x=13#

#color(blue)(2x-7)=color(green)(6+x#

Subtract #color(blue)(x# both sides:

#rarr color(blue)(x-7)=color(green)(6#

#rarrcolor(blue)( x)=color(green)(6+7)#

#rarr color(blue)(x)=color(green)(13#

Check:

Substitute the value of #color(blue)(x# into the equation:

#color(brown)(2(13)-7=6+13#

#color(brown)(26-7=19#

#color(brown)(19=19#

So,the solution is true :)