Question

How do you solve `2x-7y=6`, `x+3y=2`?

Answer 1

`(x,y) = (32/13, -2/13)`

Explanation:

`x=2-3y` using the second equation, define x in terms of y
`2(2-3y)-7y=6` plug the above into the first equation
`4-6y-7y=6` distribute
`4-13y=6`
`13y=-2`
`y=-2/13`
Going back to the first equation, we can plug this value in for y to achieve x.
`x=2-3(-2/13)`
`x=26/13+6/13`

`x=32/13`