How do you solve $2 x - 8 = 1 - 4 x$ $2x - 8= 1- 4x$ ?

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How do you solve $2 x - 8 = 1 - 4 x$ $2x - 8= 1- 4x$ ?

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Answer 1 · 2017-06-04T19:59:57

See a solution process below:

Explanation:

First, add $4 x$ $color(red)(4x)$ and $8$ $color(blue)(8)$ to each side of the equation to isolate the $x$ $x$ term while keeping the equation balanced:

$2 x - 8 + 4 x + 8 = 1 - 4 x + 4 x + 8$ $2x - 8 + color(red)(4x) + color(blue)(8) = 1 - 4x + color(red)(4x) + color(blue)(8)$

$2 x + 4 x - 8 + 8 = 1 + 8 - 4 x + 4 x$ $2x + color(red)(4x) - 8 + color(blue)(8) = 1 + color(blue)(8) - 4x + color(red)(4x)$

$(2 + 4) x - 0 = 9 - 0$ $(2 + color(red)(4))x - 0 = 9 - 0$

$6 x = 9$ $6x = 9$

Now, divide each side of the equation by $6$ $color(red)(6)$ to solve for $x$ $x$ while keeping the equation balanced:

$\frac{6 x}{6} = \frac{9}{6}$ $(6x)/color(red)(6) = 9/color(red)(6)$

$(color(red)(cancel(color(black)(6)))x)/cancel(color(red)(6)) = (3 xx 3)/color(red)(3 xx 2)$

$x = (color(red)(cancel(color(black)(3))) xx 3)/color(red)(color(black)(cancel(color(red)(3))) xx 2)$

$x = 3/2$

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How do you solve $2 x - 8 = 1 - 4 x$ $2x - 8= 1- 4x$ ?

1 Answer

Explanation:

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