How do you solve #|2x + 9| < 25#?

1 Answer
Dec 14, 2016

The solution is x is in the range: #-17 < x < 8#

Explanation:

Because this problem involves and inequality with an absolute value function we must set up a system of inequalities because the absolute value function will transform a negative or positive number to a positive number. We can rewrite this problem as:

#-25 < 2x + 9 < 25#

Now we can solve for #x# while keeping the entire system balanced:

#-25 - 9 < 2x + 9 - 9 < 25 - 9#

#-34 < 2x < 16#

#(-34)/2 < (2x)/2 < 16/2#

#-17 < (cancel(2)x)/cancel(2) < 8#

#-17 < x < 8#