How do you solve #2x - 9\geq 3x + 1#?

1 Answer
Jim G.
Oct 7, 2016

#x<=-10#

Explanation:

Collect terms in x to the left side of the inequation and numeric values to the right side.

subtract 3x from both sides.

#2x-3x-9>=cancel(3x)cancel(-3x)+1#

#rArr-x-9>=1#

add 9 to both sides.

#-xcancel(-9)cancel(+9)>=1+9#

#rArr-x>=10#

To solve for x, multiply both sides by - 1.

However, because this is an inequation when we multiply/divide by a negative value, we must #color(blue)"reverse the inequality symbol"#

#(-1xx-x)<=(-1xx10)larr" reverse symbol"#

#rArrx<=-10" is the solution"#

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