How do you solve #{3-1^{2}--1\times 2}{2\times -1\times 2^{2}}#?

1 Answer
EZ as pi
Nov 5, 2016

#-32#

Explanation:

In any expression with multiple operations, always count the number of terms first. Each term will simplify to a single answer and they can be added or subtracted in the last step.

Within each term, the operations are done from strongest to weakest:
Brackets always first
Powers and roots
Multiply and divide
add and subtract

#{3-color(blue)(1^2)-color(red)(-1\xx 2)}{2xx -1xx color(lime)(2^2)}" "larr# only 1 term

#={3-color(blue)(1-color(red)(-2)}}{2xx -1xx color(lime)(4)}" "larr# do each factor

#={3-color(blue)(1color(red)(+2)}}{2xx color(lime)(-4)}#

#={2color(red)(+2)}{color(lime)(-8)}#

#={color(red)(+4)}xx{color(lime)(-8)}#

#=-32#

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