How do you solve #3/(2k+1)=2/9#?

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Answer 1 · 2018-07-28T20:39:20

#k=25/4#

We can cross multiply to now have the equation

#3(9)=2(2k+1)#, which simplifies to

#27=4k+2#

To get our #k# terms on one side, let's subtract #2# from both sides to get

#4k=25#

Lastly, let's divide both sides by #4# to get

#k=25/4#

Hope this helps!