# How do you solve 3( 2p + 19) + 2p = 8p?

Apr 22, 2017

p does not exist.

#### Explanation:

This is the step-by-step procedure of solving for p:
(ignore this if you are familiar with algebra)

Expand the the bracket:
32p = 6p
3
19 = 57

Then put it altogether
6p + 57 + 2p = 8p.

Put all values with p to one side of the equation
6p - 8p+ 2p = -57
and as 57 is positive, changing it to the other side with make it negative, the same applies to 8p.

Then simplify:
0 = -57.
As this is false, p does not exist.

It would not be within the field of real numbers.

Apr 22, 2017

See explanation

#### Explanation:

Begin by distributing $3$ to $2 p$ and $19$

$\textcolor{g r e e n}{3} \left(\textcolor{b l u e}{2 p + 19}\right) + 2 p = 8 p \to 6 p + 57 + 2 p = 8 p$

Combine like terms:

$\textcolor{b l u e}{6 p} + 38 + \textcolor{b l u e}{2 p} = 8 p \to 8 p + 57 = 8 p$

We can subtract $8 p$ from both sides to keep the variable on one side but if we do, our variable no longer has any value and thus we cannot complete the problem.

$\cancel{8 p - 8 p} + 57 = 8 p - 8 p \to 57 = 0 p \to 57 = 0$

There is nothing that would make $57 = 0$ true. There is perhaps a typo in the question or there is no solution.