How do you solve #3( 2x - 3) \leq x + 1#?

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Answer 1 · 2017-10-06T00:40:51

#x<=2#

Solve:

Use the same method you would use for solving an equation.

#3(2x-3)<=x+1#

Expand.

#6x-9<=x+1#

Subtract #x# from both sides.

#6x-9-x<=1#

Simplify.

#5x-9<=1#

Add #9# to both sides.

#5x<=1+9#

Simplify.

#5x<=10#

Divide both sides by #5#.

#x<=10/5#

Simplify.

#x<=2#