Question

How do you solve `3^(-3p)=3^(3p)`?

Answer 1

We have

`3^(-3p)=3^(3p)`

`1/(3^(3p))=3^(3p)`

`1=3^(3p+3p)`

`1=3^(6p)`

`ln1=6*p*ln3` (take logarithms on both sides)

`0=p*(6*ln3)`

`p=0`

Hence `p=0`

Answer 2

We have

`3^(-3p)=3^(3p)`

`1/(3^(3p))=3^(3p)`

`1=3^(3p+3p)`

`1=3^(6p)`

`ln1=6*p*ln3` (take logarithms on both sides)

`0=p*(6*ln3)`

`p=0`

Hence `p=0`