How do you solve #3( 3x - 4) = 42#?

1 Answer
Jun 17, 2017

See a solution process below:

Explanation:

First, divide each side of the equation by #color(red)(3)# to eliminate the parenthesis while keeping the equation balanced:

#3(3x - 4) = 42#

#(3(3x - 4))/color(red)(3) = 42/color(red)(3)#

#(color(red)(cancel(color(black)(3)))(3x - 4))/cancel(color(red)(3)) = 14#

#3x - 4 = 14#

Next, add #color(red)(4)# to each side of the equation to isolate the #x# term while keeping the equation balanced:

#3x - 4 + color(red)(4) = 14 + color(red)(4)#

#3x - 0 = 18#

#3x = 18#

Now, divide each side of the equation by #color(red)(3)# to solve for #x# while keeping the equation balanced:

#(3x)/color(red)(3) = 18/color(red)(3)#

#(color(red)(cancel(color(black)(3)))x)/cancel(color(red)(3)) = 6#

#x = 6#