How do you solve #3[-3x+4-7(x+1)]=2x+5#?

1 Answer
Robert C.
Jul 14, 2017

#x#= #-7/16#

Explanation:

Expand and simplify the equatiion

#3[-3x + 4 - 7(x + 1)] = 2x + 5#
#3[-3x + 4 - 7x - 7)] = 2x + 5#
#3(-10x - 3) = 2x + 5#
#-30x - 9 = 2x + 5#

Isolate #x#

#-30x = 2x + 14#
#-32x = 14#
#x = -14/32 = -7/16#

Sub #x = -7/16# into the original equation to test

#3[-3(-7/16) + 4 - 7((-7/16) + 1)] = 2(-7/16) + 5#
#3[(21/16) + 4 - 7(9/16)] = -14/16 + 5#
#3(21/16 + 4 - 63/16) = 66/16#
#3(22/16) = 66/16#
#66/16 = 66/16#

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