Question

How do you solve `3[-3x+4-7(x+1)]=2x+5`?

Answer 1

`x`= `-7/16`

Explanation:

Expand and simplify the equatiion

`3[-3x + 4 - 7(x + 1)] = 2x + 5`
`3[-3x + 4 - 7x - 7)] = 2x + 5`
`3(-10x - 3) = 2x + 5`
`-30x - 9 = 2x + 5`

Isolate `x`

`-30x = 2x + 14`
`-32x = 14`
`x = -14/32 = -7/16`

Sub `x = -7/16` into the original equation to test

`3[-3(-7/16) + 4 - 7((-7/16) + 1)] = 2(-7/16) + 5`
`3[(21/16) + 4 - 7(9/16)] = -14/16 + 5`
`3(21/16 + 4 - 63/16) = 66/16`
`3(22/16) = 66/16`
`66/16 = 66/16`