How do you solve #(3/4)x - (1/2)y = -(1/2)# and #x + y = -(3/2)#?

1 Answer
Jun 26, 2018

Answer:

Using substitution, we can find that #x=1# and #y=-5/2#.

Explanation:

Let's solve the second equation for one variable. We'll choose #x# first:

#x=-3/2-y#

Let's now plug that into our first equation:

#3/4(-3/2-y)-1/2y=-1/2#
#-9/8-3/4y-1/2y=-1/2#
#-9/8-3/4y-2/4y=-1/2#
#-9/8-1/4y=-1/2#
#-1/4y=-1/2+9/8#
#-1/4y=-4/8+9/8#
#(-1/4y)/(-1/4)=(5/8)/(-1/4)#
#y=-5/2#

Let's now take our y-value and put that into our equations solved for #x#:

#x=-3/2-(-5/2)#
#x=-3/2+5/2=2/2=1#

Hope this helped!