# How do you solve -3.45- 2.3( 8.6) \div 0.5?

Oct 27, 2017

$- \frac{4301}{100}$

#### Explanation:

$- 3.45 - 2.3 \left(8.6\right) \div 0.5$

Rearrange!

$- \frac{3.45}{100} - \frac{2.3}{10} \left(\frac{8.6}{10}\right) \div \frac{0.5}{10}$

$- \frac{345}{100} - \frac{23}{10} \left(\frac{86}{10}\right) \div \frac{5}{10}$

Using the rule of BODMAS..

Therefore we'll solve the Bracket and Division First!

Bracket!

$- \frac{345}{100} - \frac{23 \times 86}{10 \times 10} \div \frac{5}{10}$

$- \frac{345}{100} - \frac{1978}{100} \div \frac{5}{10}$

Division!

$- \frac{345}{100} - \frac{1978}{100} \div \frac{5}{10}$

$- \frac{345}{100} - \frac{1978}{100} \times \frac{10}{5}$

$- \frac{345}{100} - \frac{1978}{\cancel{100}} _ 10 \times {\cancel{10}}^{1} / 5$

$- \frac{345}{100} - \frac{1978}{10} \times \frac{1}{5}$

Multiplication!

$- \frac{345}{100} - \frac{1978}{10} \times \frac{1}{5}$

$- \frac{345}{100} - \frac{1978 \times 1}{10 \times 5}$

$- \frac{345}{100} - \frac{1978}{50}$

Subtraction!

$- \frac{345}{100} - \frac{1978}{50}$

Taking LCM..

$\frac{- 345 - \left(2 \times 1978\right)}{100}$

$\frac{- 345 - 3956}{100}$

$- \frac{4301}{100}$