How do you solve #-3( 4b + 4) + ( 13b - 9) = 0#?

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Answer 1 · 2018-07-06T00:19:58

#b=21#

Given that

#-3(4b+4)+(13b-9)=0#

#-12b-12+13b-9=0#

#b-21=0#

#b=21#

Answer 2 · 2018-07-06T00:29:45

#b=21#

We can distribute the #-3# to the #4b+4# term to get

#-12b-12+13b-9=0#

We can combine our like terms to get

#b-21=0#

Adding #21# to both sides, we get

#b=21#

Hope this helps!