How do you solve $3(4x-3) - (x+7) = 5(10-x)$ ?

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Answer 1 · 2017-08-13T04:17:10

$x=33/8$

Refer to the explanation for the process.

Solve:

$3(4x-3)-(x+7)=5(10-x)$

Expand using the distributive property: $a(b+c)=ab+ac$ .

$12x-9-x-7=50-5x$

Simplify.

$11x-16=50-5x$

Add $5x$ to both sides.

$11x+5x-16=50$

Add $16$ to both sides.

$11x+5x=50+16$

Simplify.

$16x=66$

Divide both sides by $16$ .

$x=66/16$

Reduce the fraction by dividing the numerator and denominator by $2$ .

$x=33/8$

How do you solve 3(4x-3) - (x+7) = 5(10-x)3(4x-3) - (x+7) = 5(10-x)?