How do you solve #3( 5 j + 2 ) = 2 ( 3 j - 6 )#?

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Answer 1 · 2016-10-12T11:23:43

#j=-2#

#3(5j+2)=2(3j-6)#

#3*5j+3*2=2*3j-2*6#

#15j+6=6j-12#

#15j-6j=-12-6#

#9j=-18#

#(cancel(9)j)/cancel(9)=-18/9#

#j=-2#