Question

How do you solve `3 * 5^(x-1) + 5^x = 0.32`?

Answer 1

`x = -1`

Explanation:

The equation can be written as `3/5 5^x + 5^x = (3/5+1)5^x =0.32`
arriving at `5^x = 0.2 = 5^(-1)` then equating exponents `x = -1`