How do you solve #-3( - 5x - 5) = 120#?

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Answer 1 · 2017-02-22T04:01:29

See the entire solution process below:

First, expand the terms within parenthesis on the left side of the equation:

#color(red)(-3)(-5x - 5) = 120#

#(color(red)(-3) xx -5x) + (color(red)(-3) xx -5) = 120#

#15x + 15 = 120#

Next, subtract #color(red)(15)# from each side of the equation to isolate the #x# term while keeping the equation balanced:

#15x + 15 - color(red)(15) = 120 - color(red)(15)#

#15x + 0 = 105#

#15x = 105#

Now, divide each side of the equation by #color(red)(15)# to solve for #x# while keeping the equation balanced:

#(15x)/color(red)(15) = 105/color(red)(15)#

#(color(red)(cancel(color(black)(15)))x)/cancel(color(red)(15)) = 7#

#x = 7#