How do you solve #-3( 8x - 5) + 6= - 123#?

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Answer 1 · 2017-11-06T15:47:26

#x=6#

#-3(8x -5)+6=-123#

Let's start by using the distributive property

#(-3)(8x)+(-3)(-5)+6=-123#

#-24x + 21 = -123#

Then subtract #21# from both sides

#-24x + 21 - 21 = -123 - 21#

#-24x= -144#

Finally, divide both sides by #-24#

#(-24x)/(-24) = (-144)/(-24)#

#x = 6#