How do you solve #-3( 8x + 9) > - 27- 24x#?

1 Answer
Oct 16, 2017

See a solution process below:

Explanation:

First, expand the terms in parenthesis on the left side of the inequality by multiplying each term within the parenthesis by the term outside the parenthesis:

#color(red)(-3)(8x + 9) > -27 - 24x#

#(color(red)(-3) xx 8x) + (color(red)(-3) xx 9) > -27 - 24x#

#-24x + (-27) > -27 - 24x#

#-24x - 27 > -27 - 24x#

Add #color(red)(24x)# and #color(blue)(27)# to each side of the inequality:

#color(red)(24x) - 24x - 27 + color(blue)(27) > color(blue)(27) - 27 - 24x + color(red)(24x)#

#0 - 0 > 0 - 0#

#0 > 0#

Because this inequality is false there is no solution to this problem. Or, the solution is the null or empty set: #{O/}#

However, if the inequality was:

#0 >= 0#

Then this is a true statement and the solution set would the the set of all Real Numbers or: #{RR}#