First, divide each side of the equation by #color(red)(3)# to eliminate the need for parenthesis while keeping the equation balanced:
#(3(9 - 6x))/color(red)(3) = -153/color(red)(3)#
#(color(red)(cancel(color(black)(3)))(9 - 6x))/cancel(color(red)(3)) = -51#
#9 - 6x = -51#
Next, subtract #color(red)(9)# from each side of the equation to isolate the #x# term while keeping the equation balanced:
#-color(red)(9) + 9 - 6x = -color(red)(9) - 51#
#0 - 6x = -60#
#-6x = -60#
Now, divide each side of the equation by #color(red)(-6)# to solve for #x# while keeping the equation balanced:
#(-6x)/color(red)(-6) = (-60)/color(red)(-6)#
#(color(red)(cancel(color(black)(-6)))x)/cancel(color(red)(-6)) = 10#
#x = 10#