How do you solve #3( - 9+ y ) = 2y - 8#?

1 Answer
smendyka
May 25, 2017

See a solution process below:

Explanation:

First, expand the terms in parenthesis on the left side of the equation by multiplying each term within the parenthesis by the term outside the parenthesis:

#color(red)(3)(-9 + y)= 2y - 8#]

#(color(red)(3) xx -9) + (color(red)(3) xx y) = 2y - 8#

#-27 + 3y = 2y - 8#

Next, add #color(red)(27)# and subtract #color(blue)(2y)# from each side of the equation to solve for #y# while keeping the equation balanced:

#-27 + 3y + color(red)(27) - color(blue)(2y) = 2y - 8 + color(red)(27) - color(blue)(2y)#

#-27 + color(red)(27) + 3y - color(blue)(2y) = 2y - color(blue)(2y) - 8 + color(red)(27)#

#0 + (3 - color(blue)(2))y = 0 + 19#

#1y = 19#

#y = 19#

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