How do you solve 3+e^(-2x)=8?

1 Answer
Oct 30, 2016

So, you've got:

3+e^(-2x)=8

Now subtract 3 from both sides of the equation:

e^(-2x)=5

From here you get:

-2x=ln(5)

*Because of logarithmic rules .

Now divide both sides of the equation by -2:

x=-1/2*ln(5)

This is your answer.