How do you solve 3+e^(-2x)=8?

Oct 30, 2016

So, you've got:

$3 + {e}^{- 2 x} = 8$

Now subtract 3 from both sides of the equation:

${e}^{- 2 x} = 5$

From here you get:

$- 2 x = \ln \left(5\right)$

*Because of logarithmic rules .

Now divide both sides of the equation by -2:

$x = - \frac{1}{2} \cdot \ln \left(5\right)$