How do you solve $- 3 \geq x + 5$ $-3\geq x + 5$ ?

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Answer 1 · 2018-03-26T05:07:11

Move all factors to one side (which is $x$ $x$ )

$- 3 \geq x + 5$ $-3>=x+5$

$- 3 - 5 \geq x + 5 - 5$ $-3-5>=x+5-5$

$- 8 \geq x$ $-8>=x$

Do remember to reverse the equation for clarity
$x \leq - 8$ $x<=-8$

How do you solve -3\geq x + 5−3≥x+5-3\geq x + 5?