How do you solve #3\leq \frac { - 6+ x } { 2}#?

1 Answer
Sep 8, 2017

#12 <= x#

Explanation:

Multiply both sides by 2:

#6 <= -6+x#

...add 6 to both sides:

#12 <= x#

and BAM.

You can verify this in your mind by saying to yourself:

"If I have any number x greater than (or equal to) 12, then, if I subtract six from that number and then divide the remainder by 2, it will be greater than (or equal to) 3."

GOOD LUCK!