# How do you solve 3\leq \frac { - 6+ x } { 2}?

Sep 8, 2017

$12 \le x$

#### Explanation:

Multiply both sides by 2:

$6 \le - 6 + x$

...add 6 to both sides:

$12 \le x$

and BAM.

You can verify this in your mind by saying to yourself:

"If I have any number x greater than (or equal to) 12, then, if I subtract six from that number and then divide the remainder by 2, it will be greater than (or equal to) 3."

GOOD LUCK!