How do you solve #3( n - 2) + 2( 4n + 1) = 29#?

1 Answer
Nov 3, 2017

n = 11

Expand brackets and simplify to get the value of "n"

Explanation:

We are given

#3*(n-2) + 2* (4*n + 1) = 29#

Expanding the brackets, we get the following:

#3*n - 6 + 8*n + 2 = 29#

Group the like terms and simplify:

#( 3 * n + 8 * n) - 6 + 2 = 29#

This can be simplified as follows:

#11 * n - 4 = 29#

#11 * n = 29 + 4# (When we move -4 to the right-hand side, we must change the sign)

Hence, we get #11*n = 33#

Therefore, n = 33 / 11 = 3#

Hence,

n = 3 (Our final answer)