How do you solve $3( n - 2) + 2( 4n + 1) = 29$ ?

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Answer 1 · 2017-11-03T08:42:04

n = 11

Expand brackets and simplify to get the value of "n"

We are given

$3*(n-2) + 2* (4*n + 1) = 29$

Expanding the brackets, we get the following:

$3*n - 6 + 8*n + 2 = 29$

Group the like terms and simplify:

$( 3 * n + 8 * n) - 6 + 2 = 29$

This can be simplified as follows:

$11 * n - 4 = 29$

$11 * n = 29 + 4$ (When we move -4 to the right-hand side, we must change the sign)

Hence, we get $11*n = 33$

Therefore, n = 33 / 11 = 3#

Hence,

n = 3 (Our final answer)

How do you solve 3( n - 2) + 2( 4n + 1) = 293( n - 2) + 2( 4n + 1) = 29?