How do you solve #3( n + 4) < - 7n + 62#?

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Answer 1 · 2018-03-03T21:31:13

The solution is #n<5#.

You can do actions on both sides of the inequality as long as they are the same on both sides.

In this case, first, add #7n# to both sides, subtract #12#, then divide by #10#.

#3(n+4)<-7n+62#

#3n+12<-7n+62#

#3n+12color(blue)(+7n)<-7n+62color(blue)(+7n)#

#3n+7n+12<-7n+7n+62#

#10n+12< color(red)cancelcolor(black)(-7n+7n)+62#

#10n+12<62#

#10n+12color(blue)(-12)<62color(blue)(-12)#

#10ncolor(red)cancelcolor(black)(+12-12)=62-12#

#10n<62-12#

#10n<50#

#n<5#

This the final solution.