How do you solve #-3( u + 4) - 2u = 2( u + 1)#?

1 Answer
Alan P.
Nov 14, 2016

#u=-2#

Explanation:

Using the distributive property
#color(white)("XXX")color(red)(-3(u+4)=-3u-12#
and
#color(white)("XXX")color(blue)(2(u+1)=2u+2#

So
#color(red)(-3(u+4))-2u=color(blue)(2(u+1))#

#rarr color(red)(-3u-12)-2u = color(blue)(2u+2)#

#rarr -5u-12=2u+2#

#rarr -7u=14#

#rarr u=-2#

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