How do you solve $-3( x - 1) = 3[ x - 4( x - 3) + x ]$ ?

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Answer 1 · 2016-10-10T05:01:00

$x=11$

$-3(x-1)=3[x-4(x-3)+x]$

$-3x+3=3[x-4x+12+x]$
$-3x+3=3x-12x+36+3x$

$-3x+3=-6x+36$
$-3x+6x=36-3$
$3x=33$
$x=33/3=11$

How do you solve -3( x - 1) = 3[ x - 4( x - 3) + x ]-3( x - 1) = 3[ x - 4( x - 3) + x ]?