How do you solve #3( x - 1) + 6= 12#?

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Answer 1 · 2017-06-17T16:53:50

#x = 3#

Given: #3(x-1) + 6 = 12#

Distribute: #" "3x - 3 + 6 = 12#

Add like terms: #3x + 3 = 12#

Isolate the variable by subtracting #3# from both sides:

#3x = 12 - 3 = 9#

Divide both sides by #3: " " (3x)/3 = 9/3#

Simplify: #" "x = 3#

CHECK:
#3(3-1) + 6 = 12#
#3(2) + 6 = 12#
#12 = 12#