How do you solve $3 (x - 2) = x + 10$ $3( x - 2) = x + 10$ ?

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Answer 1 · 2016-10-20T12:39:08

$x = \frac{16}{3} or 5.33$ $x=16/3 or 5.33$

Distribute the $3$ $3$ throughout the set of parenthesis on the left

$3 x - 6 = x + 10$ $3x-6=x+10$

Begin to isolate $x$ $x$ by adding $2$ $2$ on both sides of the equation

$3 x = 16$ $3x=16$

Isolate $x$ $x$ by dividing both sides of the equation by $3$ $3$

$x = \frac{16}{3} or 5.33$ $x=16/3 or 5.33$

How do you solve 3( x - 2) = x + 103(x−2)=x+103( x - 2) = x + 10?