How do you solve #|- 3( x - 7) | = 21#?

1 Answer
Apr 12, 2018

#x = 0# and #x = 14#

Explanation:

Because #|21| = |-21| = 21#, we can remove the absolute value from the equation as such

#|-3(x-7)| = 21#
#-3(x-7) = +- 21#

We then have two equations (differentiated by the #+-# sign) and we solve each using equation manipulation.

#-3(x-7) = 21#
#21 - 3x = 21#
#3x = 0 -> x = 0#

#-3(x-7) = -21#
#21 - 3x = -21#
#42 = 3x#
#x = 42/3 = 14#

Thus, our two solutions are #x = 0# and #x = 14#.