How do you solve #3(y+3)+5y=4(2y+1)+5#?

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Answer 1 · 2016-09-24T17:53:42

All values of #y# are correct for this equation

Expand the brackets

#3y + 9 + 5y = 8y + 4 +5#

Gather like terms

#8y + 9 = 8y + 9#

Take 9 from both sides

#8y = 8y#

Divide both sides by #8#

#y=y#