How do you solve #31- y \geq 8( y - 4)#?

1 Answer
Jan 5, 2018

#y<=7#

Explanation:

The key to understanding linear inequalities is not to get confused by the sign, here we have #31-y# is greater than or equal to #8(y-4)#, so we need to find a value for #y# which supports this.

To solve for #y#, it is much like a normal linear equation, the only difference being that if we divide or multiply by a negative number, we switch the side.

So to start with, we must first expand the bracket.

#therefore# #31-y >= 8(y-4)#

#31-y >= 8y-32#

Now we need to rearrange for like terms, therefore we move the #y# over and #32# as we would a linear equation.

#therefore# #63 >=9y# which is the same as #9y<=63#

Now we divide by 9.

#y<=7#

Therefore, if #y# is 7 or less it will hold this inequality true.