# How do you solve 32=2^(x+4)?

May 20, 2016

The solution is $x = 1$

#### Explanation:

To solve such equation we first have to write the number $32$ as a power of $2$.

$32 = {2}^{x + 4}$

${2}^{5} = {2}^{x + 4}$

Now we can change the equation with powers to the equality of exponents.

$5 = x + 4$

$x = 5 - 4$

$x = 1$