Question

How do you solve `36v ^ { 2} - 132v + 121= 0`?

Answer 1

See below.

Explanation:

This is actually a perfect square.

`36v ^ { 2} - 132v + 121= (6v-11)^2`
(To see why, try expanding `(ax-b)^2`, and setting equal powers to each other)

`(6v-11)^2=0`

`6v=11`

`v=11/6`.