How do you solve 37x - 15= 38?

1 Answer
Nov 6, 2017

x~~1.4

Explanation:

In this problem, you're expected to isolate x on one side of the equation, and every other aspect of the equation (including a negative, if you end up with a (-x) at the end) on the other side of the =.

To do this, you use a process called "balancing the equation," which is essentially working backwards with PEMDAS.

The first part, since we're going backwards, is addition or subtraction. We see there is a -15, which we can clear from that side by adding 15 to both sides. It looks like this:

37x-15+15=38+15

Since -15+15=0,

37x cancel(-15+15)=38+15

Giving us, after simplifying the right side by adding 38 and 15:

37x=53

Since x is being multiplied by 37, the next step we can use working backwards from PEMDAS is division, to cancel out the multiplication. Do this to both sides as well.

"37x"-:"37"="53"-:"37"

Simplify.

x~~1.4