Question

How do you solve `-39\leq 5x - 9= 16`?

Answer 1

`-39/5 <= x = 5`

Explanation:

`-39 <= 5x - 9 = 16`

This equation is in two phase, you have to solve each equally and separately..

We have..

`-39<= 5x -> "First phase"`

`5x - 9 = 16 -> "Second phase"`

Solving the first..

`-39 <= 5x`

Divide both sides by `color(red)5`

`-39/color(red)5 <= (5x)/color(red)5`

`-39/5 <= cancel(5x)/cancel5`

`-39/5 <= x`

Solving the second phase..

`5x - 9 = 16`

Add `color(blue)9` to both sides

`5x - 9 color(blue)(+9) = 16 color(blue)(+9)`

`5x - 9 + 9 = 16 + 9`

`5x + 0 = 25`

`5x = 25`

Divide both sides by `color(green)5`

`(5x)/color(green)5 = 25/color(green)5`

`cancel(5x)/cancel5 = 25/5`

`x = 25/5`

`x = 5`

Now combining both answers we have..

`-39/5 <= x = 5 -> Answer`