How do you solve #-3a + 5= 23#?

2 Answers
Feb 4, 2017

See the entire solution process below:

Explanation:

First, subtract #color(red)(5)# from each side of the equation to isolate the #a# term while keeping the equation balanced:

#-3a + 5 - color(red)(5) = 23 - color(red)(5)#

#-3a + 0 = 18#

#-3a = 18#

Now, divide each side of the equation by #color(red)(-3)# to solve for #a# while keeping the equation balanced:

#(-3a)/color(red)(-3) = 18/color(red)(-3)#

#(color(red)(cancel(color(black)(-3)))a)/cancel(color(red)(-3)) = -6#

#a = -6#

Feb 4, 2017

#a=-6#

Explanation:

Isolate the -3a term by subtracting 5 from both sides of the equation.

#-3acancel(+5)cancel(-5)=23-5#

#rArr-3a=18#

To solve for a, divide both sides by - 3

#(cancel(-3) a)/cancel(-3)=18/(-3)#

#rArra=-6#

#color(blue)"As a check"#

Substitute this value into the left side and if it is equal to the right side then it is the solution.

#"left side "=(-3xx-6)+5=18+5=23#

#rArra=-6" is the solution"#