How do you solve #-3a + 5= 23#?
2 Answers
See the entire solution process below:
Explanation:
First, subtract
Now, divide each side of the equation by
Explanation:
Isolate the -3a term by subtracting 5 from both sides of the equation.
#-3acancel(+5)cancel(-5)=23-5#
#rArr-3a=18# To solve for a, divide both sides by - 3
#(cancel(-3) a)/cancel(-3)=18/(-3)#
#rArra=-6#
#color(blue)"As a check"# Substitute this value into the left side and if it is equal to the right side then it is the solution.
#"left side "=(-3xx-6)+5=18+5=23#
#rArra=-6" is the solution"#