How do you solve 3a+b=43a+b=4 and a-2b=6a2b=6 using substitution?

1 Answer
Mar 3, 2018

(a,b)to(2,-2)(a,b)(2,2)

Explanation:

3a+b=4to(1)3a+b=4(1)

a-2b=6to(2)a2b=6(2)

"from equation "(2)" we obtain "a=6+2bto(3)from equation (2) we obtain a=6+2b(3)

color(blue)"substitute "a=6+2b" into equation "(1)substitute a=6+2b into equation (1)

rArr3(6+2b)+b=43(6+2b)+b=4

rArr18+6b+b=418+6b+b=4

rArr18+7b=418+7b=4

"subtract 18 from both sides"subtract 18 from both sides

cancel(18)cancel(-18)+7b=4-18

rArr7b=-14

"divide both sides by 7"

(cancel(7) b)/cancel(7)=(-14)/7

rArrb=-2

color(blue)"substitute "b=-2" in equation "(1)

3a-2=4

rArr3a=4+2=6

rArra=6/3=2

"the solution is "a=2,b=-2