Question

How do you solve `3abs(x-1)+2>=8`?

Answer 1

If `3abs(x-1)+2 >=8`
then
`3abs(x-1)>=6`
and
`abs(x-1)>=2`

If `(x-1)` is negative then
`1-x>=2`
`-x>=1`
`x<=-1`

If `(x-1)` is positive or zero
`x-1 >= 2`
`x>=3`

So `3abs(x-1)+2>= 8`
if
`x<-1`
or
`x>=3`