How do you solve $3 c - 7 = - c + 1$ $3c - 7= - c + 1$ ?

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Answer 1 · 2016-11-01T23:26:36

$c = 2$ $c=2$

$3 c - 7 = - c + 1$ $3c-7 = -c+1$

1) Add 1c to remove variable from right side
$4 c - 7 = 1$ $4c-7 = 1$

2) Add 7 to remove number from left side
$4 c = 8$ $4c = 8$

3) Divide by 4 on both sides
$c = 2$ $c = 2$

How do you solve 3c - 7= - c + 13c−7=−c+13c - 7= - c + 1?