How do you solve #3e^x+1=5#?

1 Answer
Jim G.
Oct 20, 2016

#x≈0.2877" to 4 dec. places"#

Explanation:

Begin by expressing the equation in terms of #e^x.#

#3e^x=4rArre^x=4/3#

Take ln (natural logarithm) of both sides.

#rArrlne^x=ln(4/3)#

#color(orange)"Reminder " color(red)(bar(ul(|color(white)(2/2)color(black)(loga^xhArrxloga)color(white)(2/2)|)))#

#rArrxcancel(lne)^1=ln(4/3)#

#rArrx=ln(4/3)≈0.2877" to 4 dec. places"#

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