# How do you solve #3e^x+1=5#?

##### 1 Answer

Oct 20, 2016

#### Explanation:

Begin by expressing the equation in terms of

#e^x.#

#3e^x=4rArre^x=4/3# Take ln (natural logarithm) of both sides.

#rArrlne^x=ln(4/3)#

#color(orange)"Reminder " color(red)(bar(ul(|color(white)(2/2)color(black)(loga^xhArrxloga)color(white)(2/2)|)))#

#rArrxcancel(lne)^1=ln(4/3)#

#rArrx=ln(4/3)≈0.2877" to 4 dec. places"#