# How do you solve 3e^x-2=0?

$x = \ln \left(\frac{2}{3}\right) \cong - 0.40546$
$3 {e}^{x} - 2 = 0$
$3 {e}^{x} = 2 \to {e}^{x} = \frac{2}{3}$
$x = \ln \left(\frac{2}{3}\right) \cong - 0.40546$