How do you solve #3j + 2= 8#?

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Answer 1 · 2018-05-02T05:07:28

#j = 2#

#3j + 2 = 8#

To solve for the variable #j#, we have to make it alone. To do so, first subtract #color(blue)2# from both sides of the equation:

#3j + 2 quadcolor(blue)(-quad2) = 8 quadcolor(blue)(-quad2)#

#3j = 6#

Now divide both sides by #color(blue)#:
#(3j)/color(blue)3 = 6/color(blue)3#

So the final answer is
#j = 2#

Hope this helps!