How do you solve 3log_4 n= 6 ?

Apr 4, 2016

$n = 16$

Explanation:

Begin with dividing both sides by three to make it much easier to approach.

$4 {\log}_{4} n = 6$
${\log}_{4} n = 2$

Now raise both sides to the power of 4, which will cancel out the logarithm

${\log}_{4} n = 2$
${4}^{{\log}_{4} n} = {4}^{2}$
$n = {4}^{2}$
$n = 16$