Question

How do you solve `3log_4 n= 6`?

Answer 1

`n = 16`

Explanation:

Begin with dividing both sides by three to make it much easier to approach.

`4log_4n = 6`
`log_4n = 2`

Now raise both sides to the power of 4, which will cancel out the logarithm

`log_4n = 2`
`4^(log_4n) = 4^2`
`n = 4^2`
`n = 16`